(3b^2+3b-5)/(b-3)

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Solution for (3b^2+3b-5)/(b-3) equation:


D( b )

b-3 = 0

b-3 = 0

b-3 = 0

b-3 = 0 // + 3

b = 3

b in (-oo:3) U (3:+oo)

(3*b^2+3*b-5)/(b-3) = 0

3*b^2+3*b-5 = 0

3*b^2+3*b-5 = 0

DELTA = 3^2-(-5*3*4)

DELTA = 69

DELTA > 0

b = (69^(1/2)-3)/(2*3) or b = (-69^(1/2)-3)/(2*3)

b = (69^(1/2)-3)/6 or b = (-(69^(1/2)+3))/6

(b+(69^(1/2)+3)/6)*(b-((69^(1/2)-3)/6)) = 0

((b+(69^(1/2)+3)/6)*(b-((69^(1/2)-3)/6)))/(b-3) = 0

( b+(69^(1/2)+3)/6 )

b+(69^(1/2)+3)/6 = 0 // - (69^(1/2)+3)/6

b = -((69^(1/2)+3)/6)

( b-((69^(1/2)-3)/6) )

b-((69^(1/2)-3)/6) = 0 // + (69^(1/2)-3)/6

b = (69^(1/2)-3)/6

b in { -((69^(1/2)+3)/6), (69^(1/2)-3)/6 }

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